(x-6)(x+4)=x^2-7x+1

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Solution for (x-6)(x+4)=x^2-7x+1 equation: 



(x-6)(x+4)=x^2-7x+1

We move all terms to the left:

(x-6)(x+4)-(x^2-7x+1)=0

We get rid of parentheses

-x^2+(x-6)(x+4)+7x-1=0

We multiply parentheses ..

-x^2+(+x^2+4x-6x-24)+7x-1=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+4x-6x-24)+7x-1=0

We get rid of parentheses

-1x^2+x^2+4x-6x+7x-24-1=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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